EDIT
Looks like what I want isn’t possible since keys in a map must be unique, so I’m looking for a workaround.
I’ve gotten as far as getting my data into a list of maps:
paths_spec = [
for this_one, values in module.api_lambdas :
values.paths_spec
if values.paths_spec != {}
]
which gives me a list(map(map(string))), but I still need to extract all those maps to look like map(map(string)) (along with duplicates) to present somewhere else. I was thinking about using a template file, but I get the following error:
Cannot include the given value in a string template: string required
Original Question
The documentation for merge states:
If more than one given map or object defines the same key or attribute, then the one that is later in the argument sequence takes precedence.
I didn’t realise until today that an edge case I have means this is not what I want somewhere that I am already using it.
This code:
paths_spec = merge([for this_one in module.api_lambdas : this_one.paths_spec]...)
results in my keys being squashed, such that if I have a key called foobar with different values than another key called foobar, those two keys are merged together. Makes sense, but what I need is for a way to not do that if the other key has different values.
Is that possible?