Use templatefile or jsonencode in local-exec command

Hi,
I have a local-exec resource running a CLI tool which need a -f (.yaml file) argument . This is the requirement . In future I will need to run this for multiple file, so I ll also build a loop I guess.

In this yaml file, I need to replace one line with a variable $myproject .

apiVersion: opa.k8smgmt.io/v3
kind: OPAConstraint
metadata:
  labels:
  name: container-limits-custom
  project: $myproject
spec:
  artifact:
    artifact:
      paths:
      - name: file://artifacts/container-limits-custom/container-limits.yaml
    options: {}
    type: Yaml
  templateName: container-limits-custom

I would like to combine directly the use of the command line and the template rendering in only one block .

Like so:
this is the basic :

resource "null_resource" "run_command" {
  provisioner "local-exec" {
   command = "  my_cli  -f ./artifacts/template.yaml"

I thought about using jsonencode() or templatefile() :

resource "null_resource" "run_command" {
  provisioner "local-exec" {
   command = "  my_cli  -f $FILE "
environment = { FILE = jsonencode("./artifacts/template.yaml")
}
} }

or :

resource "null_resource" "run_command" {
  provisioner "local-exec" {
   command = "  my_cli  -f $FILE "
environment = { FILE = templatefile("./artifacts/template.yaml",  { myproject = var.myproject  } )
}
} }

Is it even possible to mix jsonencode() or templatefile() as part of a local-exec , and is doing so in an environment argument a good approach ?